WebNov 24, 2012 · Defining max on arrays is, as it says in the exception, ambiguous. If we have the following arrays: [6, 2], [5, 1], then I guess the output should be [6, 2], but if we have the following example: [6, 2], [7, 1] what would then the output have to be. In fact there are so many different definitions of max here. WebOct 21, 2015 · 1. As others have mentioned, you can answer this inquiry in more general terms (even without additional libraries). maxval = max (map (max, resultlist)) print …
Python List max() Method - GeeksforGeeks
WebApr 14, 2012 · If you want to get the indices of the three largest values, you can just slice the list. >>> sort_index (score) [:3] [2, 1, 4] It also supports sorting from smallest to largest by using the parameter rev=False. >>> sort_index (score, rev=False) [3, 0, 4, 1, 2] Share Follow answered Nov 5, 2024 at 12:09 Troll 1,859 3 15 33 Add a comment WebWhen you slice a list in Python with [start:end] syntax, the start is included and the end is omitted. def eleMax (items, start=None, end=None): return max (items [slice (start, end)]) When operating over large lists or many calls to this you can avoid the overhead of the slice creating a new list and copying the pointers. flea bites on humans photos
Python: Get Index of Max Item in List • datagy
WebJul 28, 2014 · @PeterDeGlopper: Good point, but it's also worth mentioning that the simplest key function for (non-ISO-format) dates is usually something like datetime.datetime.strptime (with a format partialed into it) or other similar way to convert them into actual date objects that know how to compare to each other.(Because many … WebNov 23, 2014 · when the list has more than one element, the minimum of the list can be obtained by comparing the first element of the list ( ll.value) to the minimum of the remaining list starting at ll.next (the tail of the list). finally it is a better practice to use the is operator to test if a Python variable is None. A working code could be the following: Web1 day ago · As a result, get_min_max_feret_from_labelim () returns a list of 1101 elements. Works fine, but in case of a big image and many labels, it takes a lot a lot of time, so I want to call the get_min_max_feret_from_mask () using multiprocessing Pool. The original code uses this: for label in labels: results [label] = get_min_max_feret_from_mask ... flea bites on legs treatment